Van der Waals's equation of state is obeyed b | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The Van der Waals equation for $n$ moles of a real gas is derived by correcting the ideal gas equation $PV = nRT$ for intermolecular forces and mo

Vedclass · Accepted Answer

$\left( P + \frac{n^2 a}{V^2} \right) (V - nb) = nRT$

Vedclass · Answer

(D) The Van der Waals equation for $n$ moles of a real gas is derived by correcting the ideal gas equation $PV = nRT$ for intermolecular forces and molecular volume.The pressure correction term is $\frac{n^2 a}{V^2}$ and the volume correction term is $nb$.Substituting these into the ideal gas equation,we get:$\left( P + \frac{n^2 a}{V^2} \right) (V - nb) = nRT$Where:$P$ = pressure of the gas$V$ = volume of the gas$n$ = number of moles$a$ and $b$ = Van der Waals constants$R$ = universal gas constant$T$ = temperature

Van der Waals's equation of state is obeyed by real gases. For $n$ moles of a real gas,the expression will be :-

Similar Questions

What is the correction term in the pressure for real gas in comparison to the ideal gas?

When does a real gas behave like an ideal gas?

The compressibility factor for a van der Waal gas at high pressure is

What are the corrections made to the pressure and volume of real gases compared to ideal gases?

Assertion : Greater the value of van der Waal's constant $a$,greater is the liquefaction of gas.
Reason : $a$ indirectly measures the magnitude of attractive forces between the molecules.

Vedclass Test Series

Exam Paper Generator

Online Exam Module